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What is the derivative dy/dx given that y^3*x^2 = 1
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The derivative `dy/dx` has to be derived for y^3*x^2 = 1.
`(d(y^3*x^2))/dx = 0`
=>` y^3*2x + 3y^2*x^2*(dy/dx) = 0`
=> `3y^2*x^2*(dy/dx) = (-y^3*2x)`
=> `(dy/dx) = (-y^3*2x)/(3y^2*x^2)`
=> `(dy/dx) = (-y*2)/(3*x)`
The required derivative is `(dy/dx) = (-2*y)/(3*x)`
Posted by justaguide on June 22, 2013 at 2:17 PM (Answer #1)
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