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What is the value of the expression `cos((23pi)/12)`?

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yapayapa | Honors

Posted August 23, 2013 at 2:23 PM via web

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What is the value of the expression `cos((23pi)/12)`?

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mathsworkmusic | (Level 3) Associate Educator

Posted August 23, 2013 at 5:42 PM (Answer #2)

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We wish to find the value of the expression `cos((23pi)/12)`.

The domain of `x` over one whole period of the cosine function `cos(x)` is ` `0 to `2pi` . If we look at a graph of a single period of the cosine function we see that it is symmetric about `x=pi`:

so that `cos(x) = cos(2pi-x)`.

Now, `(23pi)/12 = ((24-1)pi)/12 = 2pi - pi/12`

Therefore, if `x= pi/12`,

`cos(pi/12) = cos(2pi-pi/12) = cos((23pi)/12)`

Reading off the graph, `cos(pi/12)` is very close to `1`. If you put it into your calculator (as 'cos' 'bracket' 'pi' / 12 'close bracket' ) you will get  `cos(pi/12) = 0.966` to 3 significant figures.

Answer ` ``cos((23pi)/12) = cos(pi/12) = 0.966` to 3 significant figures

 

 

 

 

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted August 23, 2013 at 2:56 PM (Answer #1)

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You may write the argument of cosine, such that:

`23pi/12 = 24pi/12 - pi/12`

Taking the cosine yields:

`cos(23pi/12) = cos(2pi - pi/12) => cos(23pi/12) = cos (pi/12)`

Using the half angle identity, yields:

`cos (pi/12) = sqrt((1 + cos(pi/6))/2)`

`cos (pi/12) = sqrt((1 + sqrt3/2)/2) => cos (pi/12) = sqrt(2 + sqrt3)/2`

Hence, evaluating the given cosine, using the half angle formula, yields `cos(23pi/12) = sqrt(2 + sqrt3)/2.`

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