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What is the coordinate of the midpoint of line segment TR with T(8, -3) and R (-6,8)...
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High School Teacher
Midpoint formula = `((x(T)+x(R))/2,(y(T)+y(R))/2)`
Midpoint of TR is `((8+(-6))/2,(-3+8)/2)=(1,5/2)`
The line parallel to y=3x+4 has a slope of 3.
We need a line through (3,10) which has a slope of 3
We use the point slope formula
In our case m=3 and `x_1` = 3 and `y_1` = 10
y - 10 = 3(x - 3)
y = 3x + 1
So a) `(1,5/2)` and b) `y=3x + 1`
Posted by beckden on December 17, 2011 at 5:44 AM (Answer #1)
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