What is the concentration of a 450 mL solution that contains 200 grams of iron (II) chloride?

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The concentration of a solution can be expressed in terms of its molarity (M). A solution with a molarity of one has a concentration of one mole of the solute in every one liter of the solution.

Here we have a solution that contains 200 grams of iron (II) chloride in 450 mL of the solution. I have taken the iron (II) chloride to be anhydrous in nature. This has a molecular mass of 126.751 g/mole.

200 g of the compound constitutes 200/126.751 = 1.577 moles.

1.577 moles dissolved in 450 mL of the solution gives a molarity of 1.577/0.450 = 3.5

The required concentration of the 450 mL solution that contains 200 g of iron (II) chloride is 3.5 M.

Moles = mass of solute/ gram molecular mass. **Solute** is the 'stuff being disolved. **Solution** is a homogeneous mixture of a solute in a solvent

. moles of **solute**

**M**olarity is defined as: ____________________

. liters of **solution**

In this problem (assuming the values given are both to 3 significant figures)

. 200g** /** 127 g / mol 1.57 mol

**M**olarity = ___________________ = ________ = 3.50 M **FeCl**2

. 450mL ***** 1 L/1000ml 0.450 L

I **ALWAYS** recommended to my students that they attach the chemical formula (eg: **FeCl**2) as a subscript behind the unit of meaure symbol (eg: M).

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