what is the complete factorization of p^3-8?

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beckden | High School Teacher | (Level 1) Educator

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The difference of two cubes is `x^3-a^3=(x-a)(x^2+xa+a^2)`

So `p^3-8=(p-2)(p^2+2p+4)`

Factoring `p^2+2p+4` using the quadradic formula is


So the complete factorization is


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