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We know that the area of the circle is given by :
`A = r^2 pi.`
`` But we are given that `A= 36pi` .
Then we will substitute into the equation to determine the value of r.
`==gt r^2 pi = 36 pi` .
Reduce `pi` .
`==gt r^2 = 36 `
`==gt r= 6 m`
`` Now we know that the radius r=6 , we will find the circumference.
`==gt C = 2rpi = 2 X 6 X pi = 12 pi.`
`` Then the circumference of the circle is 12`pi` m.
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