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What is the center and radius of the circle with this given equation x^2+y^2-8x+10y+32 = 0
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The center and radius of the circle represented by x^2+y^2-8x+10y+32 = 0 has to be determined.
x^2+y^2-8x+10y+32 = 0
=> x^2 - 8x + 16 + y^2 + 10y + 25 = 9
=> (x - 4)^2 + (x + 5)^2 = 3^2
The center of the circle is (4, -5) and the radius is 3
Posted by justaguide on June 15, 2013 at 4:41 PM (Answer #1)
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