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What is the area of a triangle with vertices at (0,0), (0, 9) and (16, 4)

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anonymousse2 | Student

Posted June 3, 2012 at 1:41 PM via web

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What is the area of a triangle with vertices at (0,0), (0, 9) and (16, 4)

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted June 3, 2012 at 1:47 PM (Answer #1)

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The area of a triangle with vertices at (0, 0), (0, 9) and (16, 4) has to be determined.

The points (0, 0) and (0, 9) lie on the y-axis. The distance between these points is 9 - 0 = 9

(16, 4) lies at a distance of 16 from the y-axis. The area of the triangle formed by the three points is given by A = (1/2)*b*h = (1/2)*9*16 = 72

The area of the triangle formed by a triangle with vertices at (0, 0), (0, 9) and (16, 4) is 72 square units

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