What is the area enclosed by the lines 3x + 2y = 8 and the x and y axes

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The area enclosed by the line 3x + 2y = 8 and the x and y axes has to be determined.

The axes are perpendicular to each other. Rewrite the equation of the line 3x + 2y = 8 as `x/(8/3) + y/4 = 1` . The intercepts of the line are 8/3 and 4.

For the area formed by the three lines, the area is `(1/2)*b*h = (1/2)*4*(8/3) = 16/3`

The area enclosed by the line 3x + 2y = 8 and the x and y axes is `16/3` square units.

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