What is antiderivative of y=`sqrt(tgx)` /(cosx)^2?

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llltkl | College Teacher | (Level 3) Valedictorian

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antiderivative of y=`int(sqrt(tgx)) /cos^2x dx`

`=int sqrttgx*sec^2x dx`

Let `u=tgx`   so, `du=sec^2xdx`

and the integral becomes

`int sqrtu du=intu^(1/2)du`



Substituting the value of u we get


where, `tgx=tanx`

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