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What is antiderivative of y=`sqrt(tgx)` /(cosx)^2?
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antiderivative of y=`int(sqrt(tgx)) /cos^2x dx`
`=int sqrttgx*sec^2x dx`
Let `u=tgx` so, `du=sec^2xdx`
and the integral becomes
`int sqrtu du=intu^(1/2)du`
Substituting the value of u we get
Posted by llltkl on July 8, 2013 at 4:24 PM (Answer #1)
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