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What is the antiderivative `int ln x/x dx`
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The integral `int ln x/x dx` has to be determined.
let `ln x = y`
`dy/dx = 1/x`
`dy = (1/x)*dx`
`int ln x/x dx`
=> `int y dy`
=> `y^2/2 + C`
=> `(ln x)^2/2 + C`
The integral `int ln x/x dx = (ln x)^2/2 + C`
Posted by justaguide on July 29, 2012 at 5:07 AM (Answer #1)
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