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What is antiderivative of function y=1/(n+1), if n is natural?
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You need to evaluate the anti-derivative of the given function, hence, you need to find its indefinite integral, such that:
Since the problem provides the information that `n in N` , hence, the coefficient `1/(n+1)` is a constant, thus, you need to bring this coefficient out of integral, such that:
`int 1/(n+1)dx = 1/(n+1) int dx`
`1/(n+1) int dx = 1/(n+1)*x + c`
Hence, evaluating the antiderivative of the given function, under the given conditions, yields` int 1/(n+1)dx = x/(n + 1) + c.`
Posted by sciencesolve on June 26, 2013 at 1:38 PM (Answer #1)
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