What is antiderivative of function y=1/(n+1), if n is natural?



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Posted on (Answer #1)

You need to evaluate the anti-derivative of the given function, hence, you need to find its indefinite integral, such that:

`int 1/(n+1)dx`

Since the problem provides the information that `n in N` , hence, the coefficient `1/(n+1)` is a constant, thus, you need to bring this coefficient out of integral, such that:

`int 1/(n+1)dx = 1/(n+1) int dx`

`1/(n+1) int dx = 1/(n+1)*x + c`

Hence, evaluating the antiderivative of the given function, under the given conditions, yields` int 1/(n+1)dx = x/(n + 1) + c.`

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