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quirozd | High School Teacher | (Level 3) Adjunct Educator

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The equation you provided:


`T=2pi\sqrt(L/9.8) `

is the equation for the period of a simple pendulum.

Since L is the only variable, then T is a function of L.

1. `T(L) = 2pi\sqrt(L/9.8)`

2. The domain is `{LinR|Lgt=0}` or  `[0,+oo)`

3. The range is `{TinR|Tgt=0}` or `[0,+oo)`

4. This is a sideways-parabola graph (a square root graph).

T = 8.98 s at L = 20 m

5. Let T = 10 s, Solve for L

The above equation is rearranged:





Now we can plug in T=10


`L=24.824 m` long to the nearest 0.001 m

6. The mass has no affect on the pendulum according to this equation.


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