What is the answer for question 9)?
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We are given that at time t=0 there is 16.32g of oxygen-19 and at time t=600sec there is .964g of oxygen-19. We are asked to find the half-life of oxygen-19:
Let n be the half-life. Then `16.32(1/2)^(600/n)=.964`
** Note that at time n the formula gives 1/2 of 16.32 as required.**
The half-life is approximately 147 seconds.
(The red line is when there is 8.16g of oxygen-19; about 147 seconds)
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