Homework Help

What is the answer for question 7. a) ? http://postimg.org/image/g4k5sc60z/

user profile pic

lkballer24 | Student, Grade 11 | (Level 1) Valedictorian

Posted May 12, 2013 at 8:49 AM via web

dislike 0 like

What is the answer for question 7. a) ?

http://postimg.org/image/g4k5sc60z/

1 Answer | Add Yours

user profile pic

pramodpandey | College Teacher | (Level 3) Valedictorian

Posted May 12, 2013 at 9:33 AM (Answer #1)

dislike 1 like

Given `f(x)=2(x-4)^2+5`

fraph of this function is

Let Inverse of  f i.e `f^(-1)(x)`  ,where

either

`f^(-1)(x)=4-sqrt((x-5)/2)`  or

or

`f^(-1)(x)=4+sqrt((x-5)/2)`  

But `f^(-1)(x)!=4+-sqrt((x-5)/2)`  otherwise it can not be function.

Its domain be all real numbers  `x>=5` .

Its graph `f^(-1)(x)=4-sqrt((x-5)/2)`

 

and

graph for

`f^(-1)(x)=4+sqrt((x-5)/2)`

But the graph of

`f^(-1)(x)=4+-sqrt((x-5)/2)`

 

Thus for one value of x , we are getting two values of `f^(-1)(x).`

So this is not possible for function.

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes