# What is the answer for question 5.a) http://postimg.org/image/v5kc6rfpp/

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The question states: Find the slope of the secant to the curve defined by `f(x)=0.25(4)^x-2`

Between 0 and 1

Between 0 and 0.5

Between 0 and 0.1

Between 0 and 0.01

Answer:

The slope of the secant line is defined by `m=(f(x_1)-f(x_0))/(x_1-x_0)`

So between 0 and 1 we have `((0.25*4-2)-(0.25*4^0-2))/1=(1-2-0.25+2)=0.75`

We repeat the same work for the rest. The answers will be:

`(0.25*4^(.5)-2-0.25+2)/0.5=0.5`

`(0.25*4^.1-2-0.25+2)/0.1=0.3717`

`(0.25*4^0.01-2-0.25+2)/0.01=0.3490`