What is the answer for question 4. a) ?

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A secant is a straight line connecting two points on a curve; therefore, the first thing we need to do is solve for the y values at the two given values of x:

x=1

-2log(1)+3 = 3

x=2

-2log(2)+3 = 2.4

Therefore, the two points are (1,3) and (2,2.4).

Slope = rise/run:

`m=(y_2-y_1)/(x_2-x_1)=(2.4-3)/(2-1)=-0.6`

Therefore, the slope of the secant line through the points on the curve at x=1 and x=2 is -0.6.

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