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What is the answer for question 4.a)? (Draw 2) http://postimg.org/image/q8ectggh3/

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lkballer24 | Student, Grade 11 | Valedictorian

Posted April 19, 2013 at 2:34 PM via web

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What is the answer for question 4.a)? (Draw 2)

http://postimg.org/image/q8ectggh3/

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted April 19, 2013 at 5:29 PM (Answer #1)

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The picture represents a parabola that opens upward, hence a>0, whose vertex (h,k) is at (3,-7), hence, you may write the equation of the corresponding quadratic function, such that:

`f(x) = a(x - h)^2 + k`

Considering a = 1 yields:

`f(x) = (x - 3)^2 - 7`

You need to represent the graph of transformed function `y = f(x - 3) + 5` , based on the graph of original function, such that:

- move vertically the red graph up 5 units: `y = f(x) + 5 => y = (x - 3)^2 - 7 + 5 => y = (x - 3)^2 - 2`

- shift the graph 3 units to the right, such that: `y = (x - 3 - 3)^2 - 2 => y = (x - 6)^2 - 2`

Hence, sketching the graph of transformed function `y = f(x - 3) + 5 = (x - 6)^2 - 2 ` yields:

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