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What is the answer for question 4.b)? (Draw 2) http://postimg.org/image/q8ectggh3/  

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lkballer24 | Student, Grade 11 | (Level 1) Valedictorian

Posted April 19, 2013 at 2:35 PM via web

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What is the answer for question 4.b)? (Draw 2)

http://postimg.org/image/q8ectggh3/

 

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted April 19, 2013 at 5:43 PM (Answer #1)

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You need to notice that the given graph is a parabola whose vertex (h,k) = (3,-7), hence, you may write the vertex form of quadratic corresponding function, such that:

`f(x) = a(x - h)^2 + k`

Considering a = 1 and replacing 3 for h and -7 for k yields:

`f(x) = (x - 3)^2 - 7`

You need to sketch the graph of the transformed function `y = -4f(x) - 2,` hence, you need to take it step by step, such that:

- performing the multiplication `-4*f(x)` yields:

`-4*f(x) = -4((x - 3)^2 - 7) => y = -4(x - 3)^2 + 28`

Since a = -4, you need to flip the graph, hence, parabola opens downward now, such that:

- you need to shift down by 2 units, `y =-4(x - 3)^2 + 28 - 2 => y =-4(x - 3)^2 + 26` , hence the new graph is represented by the red parabola, such that:

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