# What is the answer for question 2) ? http://postimg.org/image/grjobmz2f/(Reminder): this is 1 question.

Asked on by lkballer24

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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to consider the following formula that helps you to find the amplitude, period and phase shift of the sine function, such that:

`y = Asin(Bx - C) + D`

`A ` represents the amplitude

`T =` `(2pi)/B` represents the equation of period

`C/B ` represents the phase shift

Comparing the equation of the given function `y = 2sin(30x - 90^o)` to the standard equation, yields that `A = 2, B = 30, C = 90^o` .

Since `A` represents the amplitude, yields that `A = 2` .

You may evaluate the period using the equation `(2pi)/B` such that:

`T = (2pi)/B => T = (2pi)/30 => T = pi/15`

You may evaluate the the phase shift using the equation `C/B` , such that:

phase shift `= C/B = 90^o/30 = 3`

Hence, evaluating the amplitude, period and phase shift, yields `A = 2, T = pi/15, C/B = 3.`

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