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A particular power boat traveling at `V_o` km/h when its power is turned off will have...

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lkballer24 | Student, Grade 11 | Valedictorian

Posted April 30, 2013 at 4:16 PM via web

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A particular power boat traveling at `V_o` km/h when its power is turned off will have its speed V given by V(t) = `V_o*10^(-0.18*t)` where t is time in seconds. If the boat was traveling at 50 km/h initially construct a table with speed at t = 0, 1, 2, 3, 4, 5.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 30, 2013 at 4:25 PM (Answer #1)

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The initial speed of the power before the power is turned off is 50 km/h. In terms of m/s the speed is `50*1000/3600` = `125/9` m/s.

The speed of the boat t seconds after the power is turned off is given by V(t) = `V_o*10^(-0.18*t)`

=> `V(t) = (125/9)*10^(-0.18*t)`

The speed of the boat t seconds after the power is turned off is:

t = 0: V = 125/9

t = 1: V = 9.176 m/s

t = 2: V = 6.062 m/s

t = 3: V = 4 m/s

t = 4: V = 2.64 m/s

t = 5: V = 1.74 m/s

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