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What are all solutions of |z-1|.|z-1|=1?
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You need to solve for `z` the equation `|z - 1|^2 = 1` , hence, considering the complex number `z = x + i*y` and replacing it for `z` in equation, yields:
`|x + i*y - 1|^2 = 1`
You need to use the formula of absolute value of a complex number `z = x + i*y` , such that:
`|z| = sqrt(x^2 + y^2) => |z|^2 = x^2 + y^2`
Reasoning by analogy, you may evaluate `|z - 1|^2` , such that:
`(x - 1)^2 + y^2 = 1`
Hence, evaluating the solutions to the given equation yields that they represent all the points `(x,y)` located on the circle whose center is at `(1,0)` and it has a radius of `1` .
Posted by sciencesolve on September 19, 2013 at 5:34 PM (Answer #1)
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