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What is the actual yield of magnesium oxide when carbon dioxide reacts with 42.8 g of...
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`2Mg+CO_2 rarr 2MgO+C`
`Mg = 24g/(mol)`
`MgO = 40g/(mol)`
`Mg:MgO = 2:2 = 1:1`
Amount of Mg moles added` = 42.8/24 =1.783`
Amount of MgO theoretical produced `= 1.783 mol`
Weight of MgO `= 1.783xx40g =71.32g`
Theoretical yield of MgO `= 71.32g`
Actual yield of MgO `= 71.31xx81.7/100 = 58.26g`
So the actual yield of MgO is 58.26g.
Posted by jeew-m on March 6, 2013 at 9:29 AM (Answer #1)
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