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What is the acceleration of a particle at x=10 m if the mass of the particle is 0.2 kg...

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portoruj | Student, Grade 10 | eNoter

Posted January 31, 2011 at 11:54 PM via web

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What is the acceleration of a particle at x=10 m if the mass of the particle is 0.2 kg ?

the  particle is moving along x axis with the potential energy U(x)= 8x^2-2x^4

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted February 1, 2011 at 1:03 AM (Answer #1)

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Work is given by the product of the force and distance. The work done contributes to an increase in potential energy.

Work = -delta U.

Force* distance = -delta U

Here we have the function of the potential energy given as U(x) = 8*x^2 - 2*x^4.

For an infinitesimally small change in distance

d/dx (Force* distance) = -U'(x)

Force = -U'(x)

U'(x) = 16x - 8x^3

At x = 10,

U'(x) = 16*10 - 8*1000

=> 160 - 8000

=> -7840

=> Force = - (-7840)

=> Force = 7840

So the force at this point is 7840.

Force is the product of the mass and acceleration. We know that the mass is 0.2 kg.

Therefore the acceleration is 7840 / 0.2 = 39200 m/s^2

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giorgiana1976 | College Teacher | Valedictorian

Posted January 31, 2011 at 11:58 PM (Answer #2)

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The acceleration is the ratio of the force and the unit mass.

Since we know the potential energy, we'll determine the intensity that is the same as acceleration.

dU/dx = d(8x^2-2x^4)/dx

dU/dx = 16x - 8x^3

Now, we'll substitute x by 10 m:

T = dU/dx

T = 16*10 - 8*10^3

T = 160 - 8000

T = a = -7840 m/s^2

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