# What is acceleration of particle if displacement y along a straight line is y=a2t^2+a1t+a0?

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You need to remember that derivative of displacement of a particle with respect to time is equal to velocity of particle such that:

`v = (dy)/(dt)`

`v = (d(a_2t^2 + a_1t + a_0))/(dt) =gt v = 2a_2t + a_1`

You need to remember that derivative of velocity of a particle with respect to time is equal to acceleration of particle such that:

`a = (dv)/(dt) =gt a = (d(2a_2t + a_1))/(dt) =gt a = 2a_2`

**Hence, evaluating the acceleration of the particle under the given condition yields `a = 2a_2` .**

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