what is the 4th term of (a-√2)^8

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llltkl | College Teacher | (Level 3) Valedictorian

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`(a+b)^n=sum_(k=0)^n(^nC_k)a^(n-k)b^k`

Therefore, the fourth term in the expansion of `(a-sqrt2)^8` is:

`^8C_3a^(8-3)(-sqrt2)^3`

` =-(8!)/(3!5!)a^5sqrt2^3`

`=-112sqrt2a^5`

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