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If we start with 9.0 grams of H2O, how many moles of H2 will be produced?
Answer the question using the balanced equation below: 2 K + 2 H2O → 2 KOH + H2 If we start with 9.0 grams of H2O, how many moles of H2 will be produced? Show your work, including all conversion factors and all units.
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Weight of H2O = 9 g
The number of mols of H2O = 9 g/ 18 g per mol
= 0.5 mol
According to stoichiometry of the given equation, 2 mols of H2O will give 1 mol of H2.
Therefore H2 produced by 0.5 mol of H2O is,
= 1/2 x 0.5 mol = 0.25 mol
Therefore 0.25 mol of H2 is produced.
the balanced reaction is
2 K + 2 H2O → 2 KOH + H2
now we have 9 g of water and the molar mass of water is 18g/mol
moles = mass/molar mass
moles of water = 9g/18(g/mol) =0.5 mol H2O
if we look ta the reaction the molar ratio is 2 H2O : 1 H2
that is 2 mol of water will produce 1 mol of H2
0.5 mol H2O*(1 mol H2/ 2 mol H2O)
0.25 mol H2
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