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If we start with 9.0 grams of H2O, how many moles of H2 will be produced?Answer the...
If we start with 9.0 grams of H2O, how many moles of H2 will be produced?
Answer the question using the balanced equation below: 2 K + 2 H2O → 2 KOH + H2 If we start with 9.0 grams of H2O, how many moles of H2 will be produced? Show your work, including all conversion factors and all units.
2 Answers | add yours
Weight of H2O = 9 g
The number of mols of H2O = 9 g/ 18 g per mol
= 0.5 mol
According to stoichiometry of the given equation, 2 mols of H2O will give 1 mol of H2.
Therefore H2 produced by 0.5 mol of H2O is,
= 1/2 x 0.5 mol = 0.25 mol
Therefore 0.25 mol of H2 is produced.
Posted by thilina-g on June 19, 2012 at 3:28 AM (Answer #1)
the balanced reaction is
2 K + 2 H2O → 2 KOH + H2
now we have 9 g of water and the molar mass of water is 18g/mol
moles = mass/molar mass
moles of water = 9g/18(g/mol) =0.5 mol H2O
if we look ta the reaction the molar ratio is 2 H2O : 1 H2
that is 2 mol of water will produce 1 mol of H2
0.5 mol H2O*(1 mol H2/ 2 mol H2O)
0.25 mol H2
Posted by chaobas on June 20, 2012 at 1:10 AM (Answer #2)
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