We have to solve the following equation (the matix in the document).
How am i meant to figure out what a=? when i have a cube?
i have done some working but i am not sure what ot do next.
the answer says --> 0,1,2
i got 1 and 2 by just using a[(a^2 -3a +2)]
i don't know what to do with the a in the front (A^3)
hope this makes sense :)
2 Answers | Add Yours
You found teh determinant to be `a^3-3a^2+2a` , and since the matrix is singular the determinant is zero.
By the zero product property at least one of the three factors must be zero. Set each factor equal to zero:
a-2=0 ==> a=2
a-1=0 ==> a=1
So the solutions are a=0,1, or 2.
that makes sense, thank you :)
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