# I want to know how to find all the values of k for which the equation Ax=b has a unique solution for every 3x1 matrix b?Consider the matrix: K -1 0 A = 2 K -1 2 1 2...

I want to know how to find all the values of k for which the equation Ax=b has a unique solution for every 3x1 matrix b?

Consider the matrix:

 K -1 0 A = 2 K -1 2 1 2

neela | High School Teacher | (Level 3) Valedictorian

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The requirement is that  the system equations  represented by Ax = b have unique solution and conditions if any on value of k .

This possible in case of  a square matrix  if all the 3 equations by Ax = b are independent or the rank of the given matrix is 3. This is possible only if the determinant of A is not equal to zero.

Therefore ||A||  nort zero.

Now let us evaluate ||A|| interms of 1st row:

Det A = k( k*2 - -1) - (-1) (2*2- -1*2) +0*(... )

Det A = k(2k+1) + 6 .

Det A  = 2k^2 +k +(6) .

DetA = 2{k^2+k/2 } + 6

DetA = 2(k^2 +k/2 +1/4) - 2/4 +6

DetA = 2(k+1/2)^2 + 11/2 ,   first term 2(+1/2)^2  is  2 times the square expression  is positive for all real k. The 2nd term 11/2 is also a positive. So therminant A is positive and is never zero. Therefore the solution of the system of equations Ax = b has unique solution for all  real values of k.