# The vertices of triangle ABC are A(-4,1),B(-4,2) and C(2,5).Find the coordinate of the point where AC cuts the y axis

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The vertices of the triangle ABC are A(-4,1), B(-4,2) and C(2,5).

The equation of the line AC is (y - 5)/(x - 2) = (1 - 5)/(-4 - 2)

=> (y - 5)/(x - 2) = 4/6

=> 6y - 30 = 4x - 8

At the point where this line touches the y-axis, the x-coordinate is 0

6y - 30 = 0 - 8

=> y = 22/6 = 11/3

**The line AC intercepts the y-axis at (0, 11/3)**