Homework Help

In a vertical magnetic field of B induction, a conductor is moving perpendicullar on...

user profile pic

catandchat | Student, College Freshman | eNotes Newbie

Posted June 30, 2009 at 1:11 AM via web

dislike 1 like

In a vertical magnetic field of B induction, a conductor is moving perpendicullar on filed, with constant speed.

 What electromotive voltage is induced in conductor?

The conductor is occupying the transverse area with radius R.

1 Answer | Add Yours

user profile pic

giorgiana1976 | College Teacher | Valedictorian

Posted June 30, 2009 at 5:07 AM (Answer #1)

dislike 0 like

The induced electromotive voltage

E=vBl

The vectorial product vxB give the orientation to the induced electromotive voltage .

The active length l is obtained from Pitagora theorem:

l=2sqrt(R^2-(R-vt)^2)

E=vBl=2vBsqrt(vt-(2R-vt)), t<2R/v

Under sqrt, the factors sum is constant, =2R, and independent by t, then the product is maxim when the factors are equal:

vt=2R-vt

t=R/v (meaning when the conductor passes through the circle center, that means that the active length is maxim)

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes