Verify if the equation log2 (x)=-1 have solutions?



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Posted on (Answer #1)

First, we'll take antilogarithm, to determine x. In this case, this means to raise the given base of logarithm, namely 2, to the power -1.

log2 (x) = -1 => x = 2^-1

We'll use the negative power property:

2^-1 = 1/2

x = 1/2

Since x>0, then 1/2 represents the solution of the equation.

Therefore, the given equation has one solution x = 1/2.

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