Verify if the equation log2 (x)=-1 have solutions?
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First, we'll take antilogarithm, to determine x. In this case, this means to raise the given base of logarithm, namely 2, to the power -1.
log2 (x) = -1 => x = 2^-1
We'll use the negative power property:
2^-1 = 1/2
x = 1/2
Since x>0, then 1/2 represents the solution of the equation.
Therefore, the given equation has one solution x = 1/2.
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