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verify: (1 + tan^2x)/(tan^2x) = csc^2x
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Middle School Teacher
(1 + tan^2x)/(tan^2x)=
Posted by anthonda49 on March 13, 2010 at 7:51 AM (Answer #1)
High School Teacher
We know the popular trigonometric identity,
Sin^2x+cos^2x = 1, Dividing by cos^2x both sides, we get:
(sinx/cosx)^2+1 = 1/cos^2. Or
tan^2x+1 = sec^2 x. Dividing both sides by tan^2x,
(tan^2x+1)/tan^2x = sec^2x/Tan^2x = (1/cos^2x)(cos^2x/sin^2x) = 1/sin^2x = sec^2x.
Posted by neela on March 13, 2010 at 10:50 AM (Answer #2)
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