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The value of (log2(3))(log3(4))(log4(5))(log5(6))(log6(7))(log7(8)) is equal to; A) 2...
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According to logarithm;
`log_ab = (log_kb)/(log_ka)`
If we consider k = 10 which is log in base 10 then;
`log_ab = (logb)/(loga)`
Similarly we can write;
So the answer is 3. Correct answer is given at option E)
Posted by jeew-m on July 10, 2013 at 11:11 AM (Answer #1)
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