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If the value of the definite integral of 1/x^2 between a and 1 is 2, what is the value...
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The value of the definite integral of `1/x^2` between a and 1 is `int_(a)^1 1/x^2 dx= 2`
`int_(a)^1 1/x^2 dx` = `-1/1 - (-1/a) = -1/1 + 1/a = 2`
=> `1/a = 2 + 1`
=> `1/a = 3`
=> a = `1/3`
The required value of a = 1/3
Posted by justaguide on November 23, 2011 at 10:33 PM (Answer #1)
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