Using the following formula d=v1t+1/2at^2 solve for a. The one is a lower case one below the v.
I understand that it's simply a mater of isolating the a variable, but I'm not sure what step to do first.
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`d=vt + (1/2)at^2` Solve for a. Please note that I have eliminated the "1" subscript from the v for clarity's sake.
The first step is to subtract v1t from both sides of the equation:
Next we need to multiply both sides by 2 to cancel the 1/2 on the right:
Finally we divide both sides by t^2:
Now we have isolated and solved for a.
The final answer is `a=(2(d-vt))/t^2`
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