Using the following formula d=v1t+1/2at^2 solve for a. The one is a lower case one below the v.

I understand that it's simply a mater of isolating the a variable, but I'm not sure what step to do first.

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`d=vt + (1/2)at^2` Solve for a. Please note that I have eliminated the "1" subscript from the v for clarity's sake.

The first step is to subtract v1t from both sides of the equation:

`d-vt=(1/2)at^2`

Next we need to multiply both sides by 2 to cancel the 1/2 on the right:

`2(d-vt)=at^2`

Finally we divide both sides by t^2:

`(2(d-vt))/t^2=a`

Now we have isolated and solved for a.

**The final answer is `a=(2(d-vt))/t^2` **

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