Use synthetic division to find the quotient and remainder

(3x^3 + 4x^2 - 7x + 6)/(x-3)

### 2 Answers | Add Yours

`3x^3+4x^2-7x+6` divided by `x-3`

`f(x)=3x^3+4x^2-7x+6 `

and

`g(x)=x-3`

`g(x)=0` if x=3

write in first row zero of g(x), and coefficients of f(x) indecreasing degree.Below second column of first row ,write zero of g(x) and multply with element in first column ,write down to third column in second row . Add these column elements in first and second row ,write down in third row.

Let write it as 3 x 3 matrix

`a_11=` zero of g(x)

`a_12=` coefficient of `x^3` , `x_13=` coefficien of `x^2` ,... so on

`a_21=a_22=0` , `a_32=a_11` , `a_23=a_11xxa_32` ,

`a_33=a_13+a_23,` `a_34=a_14+a_24`

and so on.Element in last column in third row is remainder.

3 3 4 -7 6

9 39 96

-------------------------------------

3 13 32 102

quotient= `3x^2+13x+32`

Remainder=120

(3x^3 + 4x^2 - 7x + 6)/(x-3)

x-3=x-a

3,4,-7,6 are resp. coffieints of x^3 ,x^2,x and constant terms

a x^3 x^2 x constant

3 3 4 -7 6 (cofficients and constants)

9 39 196

------------------------------------------------

3 13 32 102

``

``

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes