Use square roots to solve the following equations; round to the nearest hundreth if necessary.  `3y^2+51=918`



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Posted on (Answer #1)


To solve for y, the 51 at the left side must be eliminated. To do so, subtract both sides by 51.



The 3 beside y^2 should be cancelled too. So, divide the equation by 3.



And, take the square root of both sides to have y only at the left.



Hence, the solution set to the equation `3y^2+51=918` is `{-17, 17}` .

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