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Use square roots to solve the following equations; round to the nearest hundreth if...

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ryan133 | (Level 1) eNoter

Posted July 21, 2013 at 6:53 PM via web

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Use square roots to solve the following equations; round to the nearest hundreth if necessary. 

`3y^2+51=918`

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mjripalda | High School Teacher | (Level 1) Senior Educator

Posted July 21, 2013 at 11:17 PM (Answer #1)

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`3y^2+51=918`

To solve for y, the 51 at the left side must be eliminated. To do so, subtract both sides by 51.

`3y^2+51-51=918-51`

`3y^2=867`

The 3 beside y^2 should be cancelled too. So, divide the equation by 3.

`(3y^2)/3=867/3`

`y^2=289`

And, take the square root of both sides to have y only at the left.

`sqrt(y^2)=+-sqrt289`

`y=+-17`

Hence, the solution set to the equation `3y^2+51=918` is `{-17, 17}` .

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