# use quadratic formula to solve x^2-6x=-10i guess you use i

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The standard quadratic equation is `ax^2+bx+c=0.`

Organize your equation using the standard form.

`x^2 - 6x + 10 = 0`

Remember quadratic formula:

`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`

Compare equations and find a,b,c.

a=1,b=-6,c=10

`x_(1,2)=(-(-6)+-sqrt((-6)^2-4*1*10))/(2*1)`

`x_(1,2)=(6+-sqrt(36-40))/(2)`

`x_(1,2)=(6+-sqrt(-4))/(2)`

Use theory of complex numbers to express `sqrt -1 = i.`

`x_(1,2)=(6+-2i)/(2)`

Reduce by 2.

`x_(1,2)=3+-i`

**ANSWER: The roots of quadratic are complex. `x_1=3+i and x_2=3-i.` **