Homework Help

 Use the quadratic formula to solve the equation:6x^2 + 5x -3 = 0

user profile pic

genieee | Student, College Freshman | (Level 3) eNoter

Posted March 31, 2011 at 1:23 PM via web

dislike 1 like

 Use the quadratic formula to solve the equation:
6x^2 + 5x -3 = 0

2 Answers | Add Yours

user profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted March 31, 2011 at 1:26 PM (Answer #1)

dislike 0 like

Given the quadratic equation:

6x^2 + 5x -3 = 0

Then we know that a = 6   b= 5   and  c = -3

We will use the quadratic formula to find the roots.

We know that:

x = [ -b +- sqrt(b^2-4ac)] / 2a

==> x1 = [ -5 + sqrt(25+4*6*3)]/ 2*6

          = ( -5 + sqrt97) / 12

==> x2= ( -5-sqrt97)/12

Then the roots are:

x = { (-5+sqrt97)/12  ,  (-5-sqrt97)/12 }

user profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted March 31, 2011 at 1:27 PM (Answer #2)

dislike 0 like

The solutions of the quadratic equation ax^2 + bx + c = 0 are given by [ -b + sqrt (b^2 - 4ac)]/2a and [ -b - sqrt (b^2 - 4ac)]/2a

The equation we have here is 6x^2 + 5x - 3 = 0

a = 6, b = 5 , c = -3

Substituting the values in the formula we get

x1 = [ -5 + sqrt (25 + 72)]/12

=> -5/12 + sqrt 97/12

x2 = -5/12 - sqrt 97/12

The solution of the equation are (-5/12 + sqrt 97/12, -5/12 - sqrt 97/12)

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes