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Use implicit differentiation to determine y' if y = e^(3x + 18)
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The function `y = e^(3x + 18)` . The derivative y' has to be determined using implicit differentiation.
`y = e^(3x + 18)`
Take the natural logarithm of both the sides
=> `ln y = 3x + 18`
Using implicit differentiation
`y'*(1/y) = 3`
=> `y' = y*3`
=> `y' = 3*e^(3x + 18)`
The derivative `y' = 3*e^(3x + 18)`
Posted by justaguide on September 21, 2012 at 7:25 PM (Answer #1)
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