Better Students Ask More Questions.
Use implicit differentiation to determine dy/dx given that sin x*cos y = tan y
1 Answer | add yours
The derivative `dy/dx` has to be determined given that sin x*cos y = tan y.
Take the derivative of both the sides with respect to x
`(d(sin x*cos y))/dx = (d(tan y))/dx`
=> `cos x - sin y*(dy/dx) = sec^2 y*(dy/dx)`
=> `(dy/dx)(sec^2y + sin y) = cos x`
=> `(dy/dx) = (cos x)/(sec^2y + sin y)`
The required derivative is `(dy/dx) = (cos x)/(sec^2y + sin y)`
Posted by justaguide on July 2, 2013 at 2:20 PM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.