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Find the minimum sample size required to estimate the population proportion. if the...
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The margin of error is given by `ME = z_(alpha/2)*sqrt((p*(1-p))/n)`
For a confidence level of 95%, `z_(alpha/2) = 1.96`
`p = 0.15, 1-p = 0.85, ME = 0.05`
Substituting the values in the formula gives:
`0.05 = 1.96*sqrt((0.15*0.85)/n)`
=> `n = (1.96/0.05)^2*(0.15*0.85)`
=> `n ~~196`
The minimum sample size is 196
Posted by justaguide on June 3, 2012 at 4:55 PM (Answer #1)
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