# Use the equation 12x-2y=16 identify the slope of the equation and the y-intercept.

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The slope and y-intercept form can be found by writing the equation as a form where y is expressed in terms of x and is the dependent term and x is the independent term.

The format is the slope-intercept form, y = mx + c, where m is the slope and c is the y-intercept.

12x - 2y = 16

=> 2y = 12x - 16

=> y = 6x - 8

**This gives the slope as 6 and the y-intercept as -8.**

For this reason, we'll have to put the equation in the point slope form.
y = mx + n, where m is the slope and n is the y intercept.
In other words, we'll have to solve for y the given equation.
We'll isolate y to the left side, shifting to the right the rest of equation:
-2y = -12x + 16
We'll divide by -2:
y = 6x – 8
Now, we can identify the slope of the equation as m = 6 and the y intercept as n = -8.

**Therefore, the slope of the equation and the y intercept are: m = 6 and n = -8.**