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Use conventional synthetic division to find (b^4-3b^3-6b^2+28b-24)/(b^3-6b^2+12b-8)

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Use conventional synthetic division to find (b^4-3b^3-6b^2+28b-24)/(b^3-6b^2+12b-8)

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__________1 _-3 _-6 _28 _-24_______8 ___________8__24
___-12 ________ -12_-36
6 ___________ 6_18
_______  __1__3__0__0___0

So `(b^4-3b^3-6b^2+28b-24)/(b^3-6b^2+12b-6) = b+3`

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