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Two solutions were titrated to the endpoint. 18.5 cm3 of 2.0 mol dm-3 HCl and 21.2...
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`NaOH+HCl rarr NaCl+H_2O`
Amount of HCl moles reacted `= 2/1000xx18.5 = 0.037`
Since the mole ration between NaOH and HCl is 1:1 we should have 0.037moles of NaOH in the solution.
Molarity is the concentration of a solution in mol/L
Let us say the molarity of the NaOH solution is Mmol/L.
`M/1000xx21.2 = 0.037`
`M = 1.745`
So the molarity of the NaOH solution is 1.745mol/L
Posted by jeew-m on March 22, 2013 at 5:18 AM (Answer #1)
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