In a two-person bobsled race, the first few seconds of the run are crucial. During a practise run on a flat ice surface,where the coefficient of...
kinetic friction for the sled is 8.00 *10^-3, the sled accelerates at 4.00m/s^2 (forward) when one person pushes with a force of 503N( forward) and the second person pushes with a force of 496N(forward). What is the mass of the empty sled?
1 Answer | Add Yours
You are only allowed to ask one question at a time. I have edited your question in accordance with that.
The sled is being pushed by two people, one exerts a force of 503 N and the other exerts a force of 496 N. The total force exerted is 503 + 496 = 999 N.
If the mass of the sled is M, we can calculate the force of kinetic friction using the given coefficient of kinetic friction as M*8*10^-3.
The net force applied on the sled is 999 - M*8*10^-3
We see that the sled is accelerated at 4 m/s^2 due to the net force.
So 999 - M*8*10^-3 = M*4
=> 999 = M(4 + 8*10^-3)
=> M = 999/4.008
=> M = 249.25 kg
The required mass of the sled is 249.25 kg
We’ve answered 317,820 questions. We can answer yours, too.Ask a question