Two particles A and B, of mass 3·1 kg and 1·8 kg respectively, connected by a light inextensible string passing over a fixed smooth pulley. Initially, B is held at rest with the string taut. It is then released.
Calculate the magnitude of the acceleration of A and the tension in the string.
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The situation is attached in the image
Using the Newton second law of motion to particle A,
`3.1g-T =3.1a` --------------(1)
Using the Newton second law of motion to particle B,
`uarrT-1.8g =1.8a` -----------------(2)
(1)/(2) `(3.1g-T)/(T-1.8g) = (3.1/1.8)`
So acceleration and tension of the string is `2.6m/s^2` and `22.34N` respectively.
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