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Two harbours p and q are 70 km apart with q bearing 90 degrees from p. ship s bears 50....
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See attached image.
`theta_(qps) = 90-50=40 deg`
`theta_(qsp) = 180-40-55=85 deg`
Using the law of sines:
Therefore, the ship is 45.2 km from the harbour at q.
Posted by crmhaske on May 19, 2013 at 2:18 AM (Answer #1)
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