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A tuning fork of unknown frequency is sounded with a 512Hz tuning fork. You hear 20...

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A tuning fork of unknown frequency is sounded with a 512Hz tuning fork. You hear 20 beats in 4.0s

a) What are the possible frequencies of the tuning fork?

b) A small elastic is placed on the tines of 512Hz tuning fork changing the frequency slightly. Now 16 beats are detected in 4.0s. What is the frequency of the unknown tuning fork and the new frequency of the weighted 512Hz tuning fork? Explain the reasoning.

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ishpiro's profile pic

Posted (Answer #2)

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I believe this was meant to be

x+ 4 = 507

x = 507 - 4 = 503

The possible new frequencies of the tuning fork with elastic are 503 Hz  and 511 Hz.

 

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supersmartpants's profile pic

Posted (Reply #1)

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"

or

x+4= 517

x=517-4=513 Hz

This is not possible.

So new frequency of  weighted tuning fork= 511 Hz.

"

Why is it not possible? Can you please explain?

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